單片機(jī)鍵盤-示例程序代碼

郭天祥鍵盤部分的代碼真是冗長(zhǎng)，難道是為了易懂，但也不是越長(zhǎng)越好懂啊，看看我寫(xiě)的。

掃描法

#include

#include

sbit we=P2^7;

sbit du=P2^6;

unsigned char code table[] = {

0x3f , 0x06 , 0x5b , 0x4f,

0x66 , 0x6d , 0x7d , 0x07,

0x7f , 0x6f , 0x77 , 0x7c,

0x39 , 0x5e , 0x79 , 0x71,

0x00};

void ini_t0();

void show();

void delayms(unsigned time);

void keyscan();

void matrixscan();

unsigned char num[6]={0,0,16,0,0,16};

unsigned char count=0;

unsigned char nums=0;

void main()

{

ini_t0();

while(1)

{

keyscan();

num[1]=nums/10;

num[0]=nums%10;

matrixscan();

show();

}

}

void matrixscan()

{

unsigned char i,j;

unsigned char temp;

for(i=0;i<4;i++)

{

P3=~(1<

if((P3|0x0f)!=0xff) //判斷此時(shí)是否有列為低電平

{ //有則得到行列位置i+1,j+1

delayms(10);

if((temp=P3|0x0f)!=0xff)

{

while((P3|0x0f)!=0xff);

for(j=0;j<4 && ( temp& 0x10<

;

num[4]=i+1;

num[3]=j+1;

break;

}

}

}

P3=0xff; //還原電平

}

void keyscan()

{

unsigned char temp;

if((P3|0x0f)!=0xff)

{

delayms(10);

if((temp=P3|0x0f)!=0xff)

{

while((P3|0x0f)!=0xff);

switch(temp)

{

case 0xef:

if(++nums==60)

nums=0;

break;

case 0xdf:

if(nums--==0)

nums=59;

break;

case 0xbf:

nums=0;

break;

case 0x7f:

TR0=~TR0;

break;

}

}

}

}

void t0_time() interrupt 1

{

TH0=(65536-45872)/256;

TL0=(65536-45872)%256;

count++;

if(count==20)

{

count=0;

if(++nums==60)

nums=0;

}

}

void ini_t0()

{

EA=1;

ET0=1;

TMOD=0x01;

TH0=(65536-45872)/256;

TL0=(65536-45872)%256;

}

void show()

{

unsigned char i;

for(i=0;i<6;i++)

{

P0=0xff;

we=1;

we=0;

P0=table[num[i]];

du=1;

du=0;

P0=~(0x20>>i);

we=1;

we=0;

delayms(1);

}

}

void delayms(unsigned time)

{

unsigned i,j;

for(i=time;i>0;i--)

for(j=110;j>0;j--)

;

}

行列反轉(zhuǎn)法，更簡(jiǎn)單的方法?？梢栽偻饧右粋€(gè) “if和延時(shí)” 來(lái)去抖動(dòng)

1 void matrixscan()

2 {

3 unsigned char temp,i;

4

5 P3=0x0f;

6 if(P3!=0x0f)

7 {

8 temp=P3;

9 P3=0xf0;

10 temp|=P3;

11 while(P3!=0xf0)

12 ;

13 for(i=0;i<4 && (temp& 0x01<

14 ;

15 num[1]=i+1;

16 for(i=0;i<4 && (temp& 0x10<

17 ;

18 num[0]=i+1;

19 }

20 }